Hi.
************************************
Javier Vizcaino. Ability Electronics. [log in to unmask]
http://www.automodelismo.com http://ability53.hypermart.net
  Starting point:        (-1)^(-1) = -1
  Applying logarithms: (-1)*ln(-1) = ln(-1)
  Since ln(-1) <> 0, dividing:  -1 = 1     (ln(-1) is
complex, but exists)


>
>There is a DEBUG routine that will delete most kinds of
partitions. The debug
>routine (below) will completely overwrite track zero of
your disk and wipe
>out all partitions. (DEBUG is a DOS command.)
It writes first sector on track 0, since dh=0 (head) and
cx=1 (bits 15-6 cilinder, 5-0 sector). BTW, having from day
1 reserved 10 bits for cilinder number caused the 1024
cilinders thing.

>
>You will need a bootable DOS diskette (95 or 98 Startup
Disk or MS-DOS
>diskette) with debug.exe on it. Please print this message
first.
>
>Be sure to mind your spaces and capital letters:

Well, DEBUG doesn't care too much. Even 'f200l200 0',
'a100', 'A100', 'movax,301', etc, work.

>debug<Enter>
>-F 200 L200 0<Enter>
>-a 100<Enter>
>-mov ax,301<Enter>
>-mov bx,200<Enter>
>-mov cx,1<Enter>
>-mov dx,0080<Enter> (change last 0 to 1 for drive D:, 2 for
drive E:)

Correctly, should be said 1 for second hard disk, 2 for
third disk, etc. Letters have no meaning at the partition
level.

>-int 13<Enter>
>-int 3<Enter>
>-<Enter>
>-G=100<Enter>


Above is very correct and will work, unless you do rare
things: it uses int 13 to do an absolute write on a hard
disk. But see that first command 'F' fills 200H bytes (one
sector) at ds:200, and int 13 with ah=3 writes using
es:[bx]. So if you make es<>ds manually, you won't write
0's.
Just after calling DEBUG, it starts with ds=es, as you can
check with 'r' (registers) command.
I suppose that the bios antivirus will be triggered doing
above. Say 'y', or disable it first. All this serves to
check if it works.

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