Hi.

>
> Over the past few days, I've run across a couple of machines that have
> baffled me.  The most recent, a '486/33 that had a passworded CMOS.  I
> disconnected the build-in battery, unplugged the power supply and
> removed all the jumpers on the board (didn't know which one was for CMOS
> clear).  I let it sit for a few minutes before reconnecting the power
> supply and powering it up.  Still passworded.

        To destroy the password, you can do:
        -If you can boot into DOS, run DEBUG and change the floppy
byte: -o 70, 10; -o 71,0, and reboot.
        -If you cannot boot into DOS, it may not be enough to disconnect
the battery: you have to make sure that the CMOS chip loses all its
voltage (mobo capacitors or the chip itself will retain charge). So if
you don't know the voltage discharge jumper you can:
                -With the battery out, leave the mobo without power
during 9^(9^9) years-light, so that it discharges itself.
                -Locate the CMOS chip and with a piece of wire touch
all its pins to mobo ground (black on the PS connector).

>  Powered off and replaced
> all of the jumpers.  Upon powering up again, there was no video.  Even
> using a different video card didn't matter.  What did I do wrong?  What
> happened.  Any ideas how I can correct this?  I'm stumped.  TIA

        Probably you messed some jumper.

> --
> Larry Atlow                          Internet:[log in to unmask]
> Microcomputer Analyst                Phonenet: (601) 264-9639
>



************************************
Javier Vizcaino. Ability Electronics. [log in to unmask]
  Starting point:        (-1)^(-1) = -1
  Applying logarithms: (-1)*ln(-1) = ln(-1)
  Since ln(-1) <> 0, dividing:  -1 = 1     (ln(-1) is complex, but exists)