Subject: | |
From: | |
Reply To: | |
Date: | Sun, 6 Jul 2014 13:53:06 -0400 |
Content-Type: | text/plain |
Parts/Attachments: |
|
|
Guys,
Unless I misunderstand, I believe patrick is looking for a formula for
optimum height above ground, not length of antenna. Unfortunately, I don't
have the answer either. Hopefully, someone else on here will.
Lou Kolb
Voice-over Artist:
Radio/TV Ads, Video narrations
Messages On-hold:
www.loukolb.com
----- Original Message -----
From: "Jim Shaffer" <[log in to unmask]>
To: <[log in to unmask]>
Sent: Sunday, July 06, 2014 12:20 PM
Subject: Re: half wave length height equation
> To get the half wave length in feet, use 468/f, where f is in MHZ.
>
> The 300 / f / 2 equasion gives you the half wave length in meters.
> --
> Jim, KE5AL
>
> -----Original Message-----
> From: Patrick Johnson
> Sent: Sunday, July 06, 2014 8:54 AM
> To: [log in to unmask]
> Subject: half wave length height equation
>
> Group,
>
> I remember QST had an article on how to figure the optim height for a
> horizontal antenna, and of course I can't find it at the moment. I am
> trying to remember the equation to figure out half wave lengths.
>
> Does the following sound correct?
>
> (H (in feet)=300/f (in MHz))/2 ?
>
> With the recent conversation about verticals I want tofigure out the
> optim height to hang a pair of G5RVs.
>
> 73s,
>
> patrick
|
|
|