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Date: | Tue, 8 Feb 2011 21:55:37 -0500 |
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Sounds great, Gary. ... Thanks!
73 from Tom Behler: KB8TYJ
----- Original Message -----
From: "Gary Lee" <[log in to unmask]>
To: <[log in to unmask]>
Sent: Tuesday, February 08, 2011 8:29 PM
Subject: Re: grounding solution for 20 m
yep. Just make sure they are not touchable.
I suspect that it is your power supply shutting down. I have had the =
same thing.
The counterpoise will help with that. chokes as well, but I would run =
the wire anyway.
Just run it around your baseboard, and maybe stuff the ends into a =
tennis ball or some such.
On Feb 8, 2011, at 6:43 PM, tom behler wrote:
> Gary:
>=20
> Thanks for the careful calculations.
>=20
> My question is:
>=20
> What do I do with the other ends of the wires?
>=20
> Just let them hang somewhere, being sure they are out of range of =
being=20
> touched by someone?
>=20
> 73 from Tom Behler: KB8TYJ
>=20
> ----- Original Message -----=20
> From: "Gary Lee" <[log in to unmask]>
> To: "tom behler" <[log in to unmask]>
> Sent: Tuesday, February 08, 2011 9:34 AM
> Subject: grounding solution for 20 m
>=20
>=20
> Tom:
>=20
> All you need to do is cut a 1/4 wave length of wire, preferrably =
something
> fairly heavy for the freq of interest.
> Remember that insulated wire has a velocity factor of around 95%.
> so, for the net freq, 300/14.258 =3D 21.041.
>=20
> This is in meters, so * 39.37 inches per meter =3D 828.377. Now * =
velocity
> factor 95% =3D 786.96 inches / 12 inch per foot =3D 65.58 / 4 =3D =
16.395.
>=20
> Now take the decimal portion and multiply by 12 =3D 4.75 near enough.
>=20
> so a length of wire about 16 feet 5 inches will be a resonant quarter =
wave
> on the blind hamns net frequency.
> Tie this to your ground on the rig and another for your amp.
> Be sure to insolate the far ends well.
>=20
>=20
> Hope this helps.
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