Hi Steve,
OK, you want to know what week day March 23 2053 will fall on.
1. If it is not the desired date of the year this year (in other words if
it is not March 23, 2011 today--which it obviously is not) you must
determine what day of the week that March 23 2011 falls on. That is your
starting point. It turns out that March 23, 2011 is on a Wednesday. So now
that you know that, proceed.
2. There are 42 years between 2011 and 2053.
3. There are 11 leap years between 2011 and 2053.
4. Adding the number of years and the number of leap years, 42 + 11 = 53.
5. Divide 53 by 7 and the answer is 7 with a remainder of 4.
6. Since your date is in the future, move that day of the week 4 days ahead
from Wednesday to Sunday and that is your answer.
So my result corresponds with your already known date of Sunday, March 23,
2053.
...And just because I'm curious, what is so special about March 23, 2053?
Is it the new projected day for the end of the world? <guffaw>!
----- Original Message -----
From: "Steve" <[log in to unmask]>
To: <[log in to unmask]>
Sent: Monday, October 10, 2011 11:39 AM
Subject: Too Much Time on My Hands
BlankOk Ron,
I think there is a missing step somewhere. How do you compute the current
date into the calculations. Let's say, for example, I want to know what day
of the week March 23, 2053 will be. Today is October 9, 2011. I know there
are 41 March 23rd yet to come, and 7 of them are leap-years. I would assume
that gives me 48. So 48/7 gives me six.
That would tell me March 23 is on a Saturday, but it is actually on a
Sunday.
I know I'm missing something, as if I did this calculation tomorrow, it
would come out with the correct result.
Steve, K8SP
From: "Ron Canazzi" <[log in to unmask]>
To: <[log in to unmask]>
Sent: Saturday, October 08, 2011 4:48 PM
Subject: Re: This will prove I have too much time on my hands, but an
interesting thing happens tomorrow.
> Hi List,
>
> Well I have a formula for figuring out what day of the week a particular
> date falls on.
>
> 1. figure out how many years the desired date if forward or backward from
> the current year.
> 2. Figure out the number of leap years between the current year and the
> desired year.
> 3. Add the 2 results from step 1 and 2.
> 4. Divide the result from step three by the number 7.
> 5. If there is no remainder, then the day of the week that the desired
> date falls on is the same as that date in the current year.
> 6. If there is a remainder, count the number of days forward or backwards
> (depending on whether your desire date is in the past or in the future)
> from
> the day the date falls on in the current year and that day of the week
> will
> be the day of the week on which the desired date falls in the desired
> year.
Steve, K8SP
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