---------- Forwarded message ----------
Date: Mon, 20 Aug 2001 21:13:24 -0700
From: Harry Marnell <[log in to unmask]>
Reply-To: Harry Marnell <[log in to unmask]>
To: JEFFREY MICHAEL KENYON <[log in to unmask]>
Cc: [log in to unmask]
Subject: Re: [Handi-Hams] the crystal formula

Jeffrey, I'm not on the other groups you posted to, so please forward this
to them...

Depends on the scanner/radio and band.  The most common scanner crystals
were the "Regency" type:

For VHF High band Crystal freq = (F/3) - 10.7   where F is the frequency
desired, divided by 3, then subtract 10.7 MHz

For example  for 162.40 on a regency type scanner:
(162.40 / 3) - 10.7  or
54.1333      -  10.7  =  43.433333 crystal freq

VHF Low band is simply Freq - 10.7

UHF is    (F / 9) - 10.7

Most Bearcat scanners used 10.8 (or was it 10.85?) as the first IF, rather
than 10.7

----- Original Message -----
From: "JEFFREY MICHAEL KENYON" <[log in to unmask]>
To: <[log in to unmask]>; <[log in to unmask]>;
<[log in to unmask]>
Sent: Monday, August 20, 2001 20:32
Subject: [Handi-Hams] the crystal formula


> Hi everyone, I am just wondering if I have this crystal format down
> correct for figuring out the frequency of the crystal I need bfor a radio
> or scanner.  Is it the frequency minus the radio's IF divided by 3 or
> something else like that?  Any help would be appreciated, and thanks in
> advance.
>
>
>
>
>